# For the following functions

Section 1.1
use a ruler or a straight edge and draw a line segment between any two points in two different quadrants (no points on an axis can be used) in Figure 1 below.
Find the distance between those points you chose, label that distance on the line segment,
Find, plot, and label the midpoint of your line segment.
Distance =
Section 1.2
In your own words, briefly describe the difference between a relation and a function. (You can delete the lines and type if you need to)
Which of the following is true about the x-intercept of a graph? (select more than one)
The x-intercept is a point that lies in Quadrant 1.
The x-intercept only lies on the x-axis.
X-intercept coordinates are of the form (0,a).
No one can show you what an x-intercept is, you have to see it for yourself.
To confirm symmetry about the y-axis for an equation such as y = x2 + 3x +2, you would do which of the following?
Substitute -y for y, then solve for y to get the original equation.
Add an x to both sides and see if the equation changes.
Substitute -x for x, then examine whether the equation is the same or not.
None of the above.
Select the relation that represents y as a function of x. Find the domain and range of those relations which are functions.
R = {(1,a), (1, b), (2,b), (3,c), (3, a), (4,a)}
R = {(1, 2), (1, 6), (2, 0.5), (5, 35), (9, 15), (9, 12)}
R = {(1,a), (2, b), (3,b), (4,c), (3, a), (4,a)}
R = {(1,a), (3, b), (5,b), (7,c), (9, a), (11,a)}
Section 1.4
Given the function f(x) = 2/x:
State the domain in interval notation: ________________________
Find f(2): __________________
The area A enclosed by a circle, in square meters, is a function of its radius r, when measured in meters. This relation is expressed by the formula A(r) = πr2 for r > 0. Find A(2) and solve A(r) = 16π. Interpret your answers to each. Why is r restricted to r > 0?
For the following functions and , find .